Factoring method for quadratic polynomials

Factoring method

WARNING: For the following lesson, you will need a tote up of indispens fitting accessories:

·Pencil ( nigh math teachers prefer this--youd want to be able-bodied to erase, anyway)

·Paper

·Graphic calculator--TI-82 or better (it must be able to let you write programs and run them)

·Knowledge of solving a quadratic equation, using the Quadratic traffic pattern, or the Quadratic Formula program, or otherwise

·You must currently be taking an algebra course, at least one semester into it (or you could use this as a for-your-information, for those of you that seduce already taken the course).

(plus, youll want some algebra homework, involving really toilsome polynomials, to drill this to)

If you are disqualified for any of these qualifications, it would be most advisable to cease your approach to this trick in mathematics until you have met these standards. Or, you can just try your best and mind if you can figure it out.

So, having trouble factoring polynomials with x shape coefficients of more than one? Lets just say you cant find twain numbers that added to drawher equal a certain number, and compute together give you another specific number. First of all, apply the discriminate test--b2-4ac--to see if it indeed can be factored.



If the substantial root of this value is not an integer (rather, if it is a decimal), it cannot be factored; it is a prime polynomial. However, if you get a whole number from this, then consider the following system of formulas (or equations, whichever sounds better for you):

x+y=z

xy=w

(NOTE: Z and W are variables that must be substituted with the good values, depending on the polynomial you are factoring)

Remember, z is the x coefficient (or mettle term) and w is the product of the x2 coefficient (or the first term) and the last term...

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